WITH RECURSIVE Clause

  • reference
  • Couchbase Server 7.6
    +
    Use the WITH RECURSIVE clause to enable recursive referencing in common table expressions.

    Purpose

    The common table expressions (CTEs) created by the WITH clause simplify complex queries and create temporary result sets which can be used as data sources or as expressions for queries.

    The WITH RECURSIVE clause is an extension of the WITH clause which enables you to create recursive queries. You can use recursive queries with hierarchical data, or data in a tree structure. In these cases, the data may have an arbitrary number of levels, and you won’t know in advance how deeply you need to traverse the data.

    The CTE for a recursive query includes a UNION or UNION ALL set operator.

    • The left arm of UNION/UNION ALL contains an anchor clause, which is non-recursive. The anchor clause produces an initial set of documents as an intermediate result set for the CTE keyspace.

    • The right arm of UNION/UNION ALL contains the recursive clause. The recursive clause produces a new set of documents.

    The recursive clause is executed again, with the CTE keyspace now referring to the result produced by the initial recursive clause. This process repeats until it results in an empty intermediate result set. The intermediate result sets are appended to produce a final output.

    Syntax

    with-recursive-clause ::= 'WITH' 'RECURSIVE' alias 'AS' '(' ( recursive-select | select | expr ) ')' cycle-clause? options-clause?
                                           ( ',' alias 'AS' '(' ( recursive-select | select | expr ) ')' cycle-clause? options-clause? )*
    Syntax diagram

    Recursive SELECT

    recursive-select ::= anchor-select ('UNION' | 'UNION ALL') recursive-select-term
    Syntax diagram

    The definition for a recursive CTE must be a SELECT statement that includes a UNION or UNION ALL set operator. If it isn’t, the CTE is treated as a non-recursive CTE.

    anchor-select

    A SELECT query that represents the anchor clause of the CTE.

    recursive-select-term

    A select term that represents the recursive clause of the CTE.

    CYCLE Clause

    cycle-clause ::= 'CYCLE' expr ( ',' expr )* 'RESTRICT'
    Syntax diagram

    The optional CYCLE clause provides one method for avoiding infinite recursions. It enables you to specify one or more fields whose values are likely to repeat.

    expr

    (Required) An identifier representing a field.

    OPTIONS Clause

    options-clause ::= 'OPTIONS' expr
    Syntax diagram

    The optional OPTIONS clause provides another method for avoiding infinite recursions. It enables you to specify that the recursion should exit after a specified level, or after accumulating a specified number of documents.

    expr

    (Required) An object with the following properties.

    Name Description Schema

    levels
    optional

    Recursion should exit after reaching this level. This assumes the anchor is at level 0.

    Integer

    documents
    optional

    Recursion should exit after accumulating this many documents.

    Integer

    Limitations

    • The recursive reference is only allowed once in the FROM clause. It’s not allowed anywhere else.

    • ORDER BY, LIMIT, and OFFSET clauses are not allowed in the SELECT statement in the subquery used to define the anchor and the recursive clause.

    • The DISTINCT quantifier is not allowed in anchor and recursive clauses.

    • GROUP BY, WINDOW, and AGGREGATE functions are not allowed in recursive clauses.

    • OUTER JOINS are not allowed in recursive clauses because they can lead to potential infinite recursion.

    • Recursive clauses do not support NEST and UNNEST clauses.

    • If there is no UNION/UNION ALL separation for the recursive CTE, the query defaults to a normal CTE.

    • A syntax error is returned when optional subclauses are used without the RECURSIVE keyword.

    • In general, recursion is also limited by:

      • The logic in the recursive statement.

      • The stop in the options argument.

      • Breaching the request timeout, if configured.

      • Breaching the request memory quota, if configured.

      • Exceeding the implicit document limit (10000) when a memory quota is not in use and when no explicit document limit is set in the options.

      • Exceeding the implicit level limit (1000) when the level option is not in use.

    Examples

    The following examples follow linear recursion. Only one recursive reference is allowed in the FROM clause. Self-joins or set-ops are not allowed in the recursive reference.

    Example 1. Simple recursive referencing
    WITH RECURSIVE cte AS (
        SELECT 1 AS r
            UNION
        SELECT cte.r+1 AS r
        FROM cte
        WHERE cte.r<4
    )
    SELECT cte.r FROM cte;
    Results
    [
      {
        "r": 1
      },
      {
        "r": 2
      },
      {
        "r": 3
      },
      {
        "r": 4
      }
    ]
    Example 2. Combine recursive and non-recursive CTEs with the WITH clause
    WITH RECURSIVE cte AS (SELECT 1 r) ,
        rcte AS (
            SELECT cte.r FROM cte
                UNION
            SELECT rcte.r+2 r FROM rcte WHERE rcte.r<7
        )
    SELECT * FROM rcte;
    Results
    [
      {
        "rcte": {
          "r": 1
        }
      },
      {
        "rcte": {
          "r": 3
        }
      },
      {
        "rcte": {
          "r": 5
        }
      },
      {
        "rcte": {
          "r": 7
        }
      }
    ]
    Example 3. Handle hierarchical or tree-structured data

    For this example, set the query context to the tenant_agent_00 scope in the travel sample dataset. For more information, see Query Context.

    Create a dataset containing employee information
    CREATE COLLECTION employees IF NOT EXISTS;
    
    INSERT INTO employees
       VALUES ("e1", {
           "employee_id": 1,
           "employee_name": "Carlos"
           }),
       VALUES ("e2", {
           "employee_id": 2,
           "employee_name": "Maya",
           "manager_id": 1
           }),
       VALUES ("e3", {
           "employee_id": 3,
           "employee_name": "Fatima",
           "manager_id": 1
           }),
       VALUES ("e4", {
           "employee_id": 4,
           "employee_name": "Yijing",
           "manager_id": 2
           }),
       VALUES ("e5", {
           "employee_id": 5,
           "employee_name": "Rahul",
           "manager_id": 3
           }),
       VALUES ("e6", {
           "employee_id": 6,
           "employee_name": "Lisa",
           "manager_id": 2
           })
    RETURNING *;
    Create an index for the employees
    CREATE INDEX e_idx ON employees(manager_id INCLUDE MISSING, employee_id, employee_name);
    Find the level of each employee in the organization
    WITH RECURSIVE emplLevel AS (
       SELECT e.employee_id, e.employee_name, 0 lvl
       FROM employees e
       WHERE manager_id IS MISSING
           UNION
       SELECT e1.employee_id, e1.employee_name, e1.manager_id, emplLevel.lvl+1
       lvl
       FROM employees e1 JOIN emplLevel
       ON e1.manager_id = emplLevel.employee_id
    )
    SELECT * FROM emplLevel;
    Results
    [
      {
        "emplLevel": {
          "employee_id": 1,
          "employee_name": "Carlos",
          "lvl": 0
        }
      },
      {
        "emplLevel": {
          "employee_id": 2,
          "employee_name": "Maya",
          "lvl": 1,
          "manager_id": 1
        }
      },
      {
        "emplLevel": {
          "employee_id": 3,
          "employee_name": "Fatima",
          "lvl": 1,
          "manager_id": 1
        }
      },
      {
        "emplLevel": {
          "employee_id": 4,
          "employee_name": "Yijing",
          "lvl": 2,
          "manager_id": 2
        }
      },
      {
        "emplLevel": {
          "employee_id": 6,
          "employee_name": "Lisa",
          "lvl": 2,
          "manager_id": 2
        }
      },
      {
        "emplLevel": {
          "employee_id": 5,
          "employee_name": "Rahul",
          "lvl": 2,
          "manager_id": 3
        }
      }
    ]
    Find the reporting hierarchy of the employees in the organization
    SELECT e.employee_id, e.employee_name, e.manager_id,
    (
        WITH RECURSIVE cte AS (
            SELECT e1.employee_id, e1.employee_name, e1.manager_id
            FROM employees e1 WHERE e1.manager_id = e.employee_id
                UNION
            SELECT e2.employee_id, e2.employee_name, e2.manager_id
            FROM employees e2, cte
            WHERE e2.manager_id = cte.employee_id
        )
        SELECT cte.* FROM cte
    ) as reports
    FROM employees e;
    Results
    [
      {
        "employee_id": 1,
        "employee_name": "Carlos",
        "reports": [
          {
            "employee_id": 2,
            "employee_name": "Maya",
            "manager_id": 1
          },
          {
            "employee_id": 3,
            "employee_name": "Fatima",
            "manager_id": 1
          },
          {
            "employee_id": 4,
            "employee_name": "Yijing",
            "manager_id": 2
          },
          {
            "employee_id": 6,
            "employee_name": "Lisa",
            "manager_id": 2
          },
          {
            "employee_id": 5,
            "employee_name": "Rahul",
            "manager_id": 3
          }
        ]
      },
      {
        "employee_id": 2,
        "employee_name": "Maya",
        "manager_id": 1,
        "reports": [
          {
            "employee_id": 4,
            "employee_name": "Yijing",
            "manager_id": 2
          },
          {
            "employee_id": 6,
            "employee_name": "Lisa",
            "manager_id": 2
          }
        ]
      },
      {
        "employee_id": 3,
        "employee_name": "Fatima",
        "manager_id": 1,
        "reports": [
          {
            "employee_id": 5,
            "employee_name": "Rahul",
            "manager_id": 3
          }
        ]
      },
      {
        "employee_id": 4,
        "employee_name": "Yijing",
        "manager_id": 2,
        "reports": []
      },
      {
        "employee_id": 6,
        "employee_name": "Lisa",
        "manager_id": 2,
        "reports": []
      },
      {
        "employee_id": 5,
        "employee_name": "Rahul",
        "manager_id": 3,
        "reports": []
      }
    ]
    Example 4. Use the OPTIONS clause and the CYCLE clause to avoid infinite recursion

    For this example, set the query context to the tenant_agent_00 scope in the travel sample dataset. For more information, see Query Context.

    Create a dataset containing product information
    CREATE COLLECTION products IF NOT EXISTS;
    
    INSERT INTO products
      VALUES (uuid(), {
        "id": 1,
        "name": "Bicycle",
        "price": 299.99,
        "description": "A sturdy and reliable bicycle.",
        "category": "Sports",
        "related_items": [2, 4]
      }),
      VALUES (uuid(), {
        "id": 2,
        "name": "Helmet",
        "price": 49.99,
        "description": "A safety helmet for cycling.",
        "category": "Sports",
        "related_items": [1, 3]
      }),
      VALUES (uuid(), {
        "id": 3,
        "name": "Water Bottle",
        "price": 9.99,
        "description": "A convenient water bottle for cycling.",
        "category": "Accessories",
        "related_items": [2, 4]
      }),
      VALUES (uuid(), {
        "id": 4,
        "name": "Gloves",
        "price": 19.99,
        "description": "Comfortable gloves for cycling.",
        "category": "Sports",
        "related_items": [1, 3]
      })
    RETURNING *;
    Create an index for the products
    CREATE PRIMARY INDEX ON `default`:`travel-sample`.`tenant_agent_00`.`products`
    Query resulting in infinite recursion
    WITH RECURSIVE similar_items AS (
      SELECT p.*, 0 as lvl FROM products p WHERE p.id=1
        UNION
      SELECT p1.*, similar_items.lvl+1 as lvl FROM products p1,
        similar_items WHERE p1.id IN similar_items.related_items
    )
    SELECT * FROM similar_items;
    Results
    [
      {
        "code": 5500,
        "msg": "Request has exceeded memory quota"
      }
    ]
    Solution using the OPTIONS clause to add a level limit
    WITH RECURSIVE similar_items AS (
      SELECT p.*, 0 as lvl FROM products p WHERE p.id=1
        UNION
      SELECT p1.*, similar_items.lvl+1 as lvl FROM products p1,
        similar_items WHERE p1.id IN similar_items.related_items
    )
    OPTIONS {"levels":2}
    SELECT * FROM similar_items;
    Results
    [
      {
        "similar_items": {
          "category": "Sports",
          "description": "A sturdy and reliable bicycle.",
          "id": 1,
          "lvl": 0,
          "name": "Bicycle",
          "price": 299.99,
          "related_items": [
            2,
            4
          ]
        }
      },
      {
        "similar_items": {
          "category": "Sports",
          "description": "A safety helmet for cycling.",
          "id": 2,
          "lvl": 1,
          "name": "Helmet",
          "price": 49.99,
          "related_items": [
            1,
            3
          ]
        }
      },
      {
        "similar_items": {
          "category": "Sports",
          "description": "Comfortable gloves for cycling.",
          "id": 4,
          "lvl": 1,
          "name": "Gloves",
          "price": 19.99,
          "related_items": [
            1,
            3
          ]
        }
      },
      {
        "similar_items": {
          "category": "Sports",
          "description": "A sturdy and reliable bicycle.",
          "id": 1,
          "lvl": 2,
          "name": "Bicycle",
          "price": 299.99,
          "related_items": [
            2,
            4
          ]
        }
      },
      {
        "similar_items": {
          "category": "Accessories",
          "description": "A convenient water bottle for cycling.",
          "id": 3,
          "lvl": 2,
          "name": "Water Bottle",
          "price": 9.99,
          "related_items": [
            2,
            4
          ]
        }
      }
    ]
    Solution using the CYCLE clause to track which fields are likely to repeat and cause a cycle
    WITH RECURSIVE similar_items AS (
      SELECT p.*, 0 as lvl FROM products p WHERE p.id=1
        UNION
      SELECT p1.*, similar_items.lvl+1 as lvl FROM products p1,
        similar_items WHERE p1.id IN similar_items.related_items
    )
    CYCLE id RESTRICT
    SELECT * FROM similar_items;
    Results
    [
      {
        "similar_items": {
          "category": "Sports",
          "description": "A sturdy and reliable bicycle.",
          "id": 1,
          "lvl": 0,
          "name": "Bicycle",
          "price": 299.99,
          "related_items": [
            2,
            4
          ]
        }
      },
      {
        "similar_items": {
          "category": "Sports",
          "description": "A safety helmet for cycling.",
          "id": 2,
          "lvl": 1,
          "name": "Helmet",
          "price": 49.99,
          "related_items": [
            1,
            3
          ]
        }
      },
      {
        "similar_items": {
          "category": "Sports",
          "description": "Comfortable gloves for cycling.",
          "id": 4,
          "lvl": 1,
          "name": "Gloves",
          "price": 19.99,
          "related_items": [
            1,
            3
          ]
        }
      },
      {
        "similar_items": {
          "category": "Accessories",
          "description": "A convenient water bottle for cycling.",
          "id": 3,
          "lvl": 2,
          "name": "Water Bottle",
          "price": 9.99,
          "related_items": [
            2,
            4
          ]
        }
      }
    ]